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x^2-1.2x-0.5=0
a = 1; b = -1.2; c = -0.5;
Δ = b2-4ac
Δ = -1.22-4·1·(-0.5)
Δ = 3.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.2)-\sqrt{3.44}}{2*1}=\frac{1.2-\sqrt{3.44}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.2)+\sqrt{3.44}}{2*1}=\frac{1.2+\sqrt{3.44}}{2} $
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